when Find the pointer manually, multi-level pointer,some time ,it will have Multiple results when searching for pointers .Most of them have no Opcodes access.It's almost impossible to do if checking each result manually.
How to use lua to remove address in the search result which without Opcode access in the result?
Check the address. If access is skipped, wait two seconds for no access, and then select Delete
The code to select the scan result is，This is enough
fl.Items[i].Selected = true
Search results displayed in the ce window
local fl = getMainForm().Foundlist3
print(fl.Items.Count) --The number of scan results
print(fl.Items[0].Caption) -- The first address
print(fl.Items[0].SubItems[0]) --The first value
print(fl.Items[0].SubItems[1]) --The first previous value
Check for access breakpoints
function debugger_onBreakpoint()
debug_continueFromBreakpoint(co_run)
ckAccess=1
debug_removeBreakpoint(fl.Items[i].Caption)
end
debug_setBreakpoint(fl.Items[i].Caption, 1,bptAccess)
The countdown
cdjs = createTimer()
local maincount = fl.Items.Count
local jsct = 3
function countdown()
if(jsct > 0 and maincount>0 )then
print(jsct)
jsct = jsct - 1
elseif (jsct == 0 and maincount>0) then
jsct = 3
maincount = maincount - 1
print("end")-- do some thing
else
print("realend") -- do some thing
cdjs.destroy()
end
end
cdjs.interval = 1000
cdjs.OnTimer = countdown
A correct logical code seems to can do this
